Electric field | Electric charge, electric force, and voltage | Physics | Khan Academy

Electric field | Electric charge, electric force, and voltage | Physics | Khan Academy


Let’s imagine that instead of
having two charges, we just have one charge by itself,
sitting in a vacuum, sitting in space. So that’s this charge here, and
let’s say its charge is Q. That’s some number,
whatever it is. That’s it’s charge. And I want to know, if I were to
place another charge close to this Q, within its sphere of
influence, what’s going to happen to that other charge? What’s going to be the
net impact on it? And we know if this has some
charge, if we put another charge here, if this is 1
coulomb and we put another charge here that’s 1 coulomb,
that they’re both positive, they’re going to repel each
other, so there will be some force that pushes the
next charge away. If it’s a negative charge and I
put it here, it’ll be even a stronger force that pulls it
in because it’ll be closer. So in general, there’s this
notion of what we can call an electric field around
this charge. And what’s an electric field? We can debate whether it really
exists, but what it allows us to do is imagine that
somehow this charge is affecting the space around it
in some way that whenever I put– it’s creating a field that
whenever I put another charge in that field, I can
predict how the field will affect that charge. So let’s put it in a little more
quantitative term so I stop confusing you. So Coulomb’s Law told us that
the force between two charges is going to be equal to
Coulomb’s constant times– and in this case, the first
charge is big Q. And let’s say that the second
notional charge that I eventually put in this field
is small q, and then you divide by the distance
between them. Sometimes it’s called r because
you can kind of view the distance as the
radial distance between the two charges. So sometimes it says r squared,
but it’s the distance between them. So what we want to do if we want
to calculate the field, we want to figure out how much
force is there placed per charge at any point around this
Q, so, say, at a given distance out here. At this distance, we want to
know, for a given Q, what is the force going to be? So what we can do is we could
take this equation up here and divide both sides by this small
1, and say, OK, the force– and I will arbitrarily
switch colors. The force per charge at this
point– let’s call that d1– is equal to Coulomb’s constant
times the charge of the particle that’s creating the
field divided by– well, in this case, it’s d1–
d1 squared, right? Or we could say, in general–
and this is the definition of the electric field, right? Well, this is the electric field
at the point d1, and if we wanted a more general
definition of the electric field, we’ll just make this a
general variable, so instead of having a particular distance,
we’ll define the field for all distances
away from the point Q. So the electric field could be
defined as Coulomb’s constant times the charge creating the
field divided by the distance squared, the distance we are
away from the charge. So essentially, we’ve defined–
if you give me a force and a point around this
charge anywhere, I can now tell you the exact force. For example, if I told you that
I have a minus 1 coulomb charge and the distance is equal
to– oh, I don’t know. The distance is equal to let’s
say– let’s make it easy. Let’s say 2 meters. So first of all, we can say,
in general, what is the electric field 2 meters
away from? So what is the electric
field out here? This is 2, right? And it’s going to be
2 meters away. It’s radial so it’s actually
along this whole circle. What is the electric
field there? Well, the electric field at
that point is going to be equal to what? And it’s also a vector
quantity, right? Because we’re dividing a vector
quantity by a scalar quantity charge. So the electric field at that
point is going to be k times whatever charge it is divided
by 2 meters, so divided by 2 meters squared, so that’s 4,
right, distance squared. And so if I know the electric
field at any given point and then I say, well, what happens
if I put a negative 1 coulomb charge there, all I have to do
is say, well, the force is going to be equal to the charge
that I place there times the electric field
at that point, right? So in this case, we said the
electric field at this point is equal to– and the units for
electric field are newtons per coulomb, and that
makes sense, right? Because it’s force divided
by charge, so newtons per coulomb. So if we know that the electric
charge– well, let me put some real numbers here. Let’s say that this
is– I don’t know. It’s going to be a really large
number, but let’s say this– let me pick
a smaller number. Let’s say this is 1
times 10 to the minus 6 coulombs, right? If that’s 1 times 10 to the
minus 6 coulombs, what is the electric field at that point? Let me switch colors again. What’s the electric field
at that point? Well, the electric field at
that point is going to be equal to Coulomb’s constant,
which is 9 times 10 to the ninth– times the charge
generating the field– times 1 times 10 to the minus
6 coulombs. And then we are 2 meters
away, so 2 squared. So that equals 9 times 10 to
the third divided by 4. So I don’t know, what is that? 2.5 times 10 to the third or
2,500 newtons per coulomb. So we know that this is
generating a field that when we’re 2 meters away, at a radius
of 2 meters, so roughly that circle around it, this is
generating a field that if I were to put– let’s say I were
to place a 1 coulomb charge here, the force exerted on that
1 coulomb charge is going to be equal to 1 coulomb times
the electric fields, times 2,500 newtons per coulomb. So the coulombs cancel out, and
you’ll have 2,500 newtons, which is a lot, and that’s
because 1 coulomb is a very, very large charge. And then a question you should
ask yourself: If this is 1 times 10 to the negative 6
coulombs and this is 1 coulomb, in which direction
will the force be? Well, they’re both positive,
so the force is going to be outwards, right? So let’s take this notion and
see if we can somehow draw an electric field around a
particle, just to get an intuition of what happens when
we later put a charge anywhere near the particle. So there’s a couple of ways to
visualize an electric field. One way to visualize it is if I
have a– let’s say I have a point charge here Q. What would be the path of a
positive charge if I placed it someplace on this Q? Well, if I put a positive charge
here and this Q is positive, that positive charge
is just going to accelerate outward, right? It’s just going to go straight
out, but it’s going to accelerate at an ever-slowing
rate, right? Because here, when you’re really
close, the outward force is very strong, and then
as you get further and further away, the electrostatic force
from this charge becomes weaker and weaker, or you could
say the field becomes weaker and weaker. But that’s the path of a–
it’ll just be radially outward– of a positive
test charge. And then if I put it here, well,
it would be radially outward that way. It wouldn’t curve the
way I drew it. It would be a straight line. I should actually use
the line tool. If I did it here, it would be
like that, but then I can’t draw the arrows. If I was here, it would
out like that. I think you get the picture. At any point, a positive test
charge would just go straight out away from our charge Q. And to some degree, one measure
of– and these are called electric field lines. And one measure of how strong
the field is, is if you actually took a unit area
and you saw how dense the field lines are. So here, they’re relatively
sparse, while if I did that same area up here– I know
it’s not that obvious. I’m getting more
field lines in. But actually, that’s not a good
way to view it because I’m covering so much area. Let me undo both of them. You can imagine if I had a lot
more lines, if I did this area, for example, in that area,
I’m capturing two of these field lines. Well, if I did that exact same
area out here, I’m only capturing one of the field
lines, although you could have a bunch more in between here. And that makes sense, right? Because as you get closer and
closer to the source of the electric field, the charge
gets stronger. Another way that you could have
done this, and this would have actually more clearly shown
the magnitude of the field at any point, is you could
have– you could say, OK, if that’s my charge Q, you
could say, well, really close, the field is strong. So at this point, the vector,
the newtons per coulomb, is that strong, that strong, that
strong, that strong. We’re just taking
sample points. You can’t possibly draw them
at every single point. So at that point, that’s
the vector. That’s the electric
field vector. But then if we go a little bit
further out, the vector is going to be– it falls off. This one should be shorter, then
this one should be even shorter, right? You could pick any point and you
could actually calculate the electric field vector, and
the further you go out, the shorter and shorter the electric
field vectors get. And so, in general, there’s all
sorts of things you can draw the electric fields for. Let’s say that this is a
positive charge and that this is a negative charge. Let me switch colors so I don’t
have to erase things. If I have to draw the path of
a positive test charge, it would go out radially from
this charge, right? But then as it goes out, it’ll
start being attracted to this one the closer it gets to the
negative, and then it’ll curve in to the negative charge and
these arrows go like this. And if I went from here, the
positive one will be repelled really strong, really strong,
it’ll accelerate fast and it’s rate of acceleration will slow
down, but then as it gets closer to the negative one,
it’ll speed up again, and then that would be its path. Similarly, if there was a
positive test charge here, its path would be like
that, right? If it was here, its path
would be like that. If it was here, it’s path
would be like that. If it was there, maybe its path
is like that, and at some point, its path might never get
to that– this out here might just go straight
out that way. That one would just go straight
out, and here, the field lines would just
come in, right? A positive test charge would
just be naturally attracted to that negative charge. So that’s, in general, what
electric field lines show, and we could use our little area
method and see that over here, if we picked a given area, the
electric field is much weaker than if we picked that
same area right here. We’re getting more field lines
in than we do right there. So that hopefully gives you
a little sense for what an electric field is. It’s really just a way of
visualizing what the impact would be on a test charge
if you bring it close to another charge. And hopefully, you
know a little bit about Coulomb’s constant. And let’s just do a very
simple– I’m getting this out of the AP Physics book, but they
say– let’s do a little simple problem: Calculate the
static electric force between a 6 times 10 to the negative
sixth coulomb charge. So 6 times– oh, no, that’s
not on an electric field. Oh, here it says: What is the
force acting on an electron placed in an external electric
field where the electric field is– they’re saying it is 100
newtons per coulomb at that point, wherever the
electron is. So the force on that, the force
in general, is just going to be the charge times the
electric field, and they say it’s an electron,
so what’s the charge of an electron? Well, we know it’s negative, and
then in the first video, we learned that its charge is
1.6 times 10 to the negative nineteenth coulombs times
100 newtons per coulomb. The coulombs cancel out. And this is 10 squared, right? This is 10 to the positive 2, so
it’ll be 10 to the minus 19 times 10 to the positive 2. The force will be minus
1.6 times 10 to the minus 17 newtons. So the problems are
pretty simple. I think the more important thing
with electric fields is to really understand intuitively
what’s going on, and kind of how it’s stronger
near the point charges, and how it gets weaker as it goes
away, and what the field lines depict, and how they can be used
to at least approximate the strength of the field. I will see you in
the next video.

98 thoughts on “Electric field | Electric charge, electric force, and voltage | Physics | Khan Academy

  1. I hope in the future only good teachers like you teach, that way student will be able to learn more efficiently.

  2. I think that's one of the main reasons he's so popular. Even youtube automatic captions gets it right most of the time!! Now that's an achievement!!

  3. why force between 2 charges is a vector quantity ????????
    what happens with the direction…????
    plzzz plzz explain ?????

  4. Because Force it's self is a vector quantity, for example Newtons second Law states that F=m * a. In relation to electrostatics it is stating that F= q * E with q being charge and E being the field. Well when the ATTRACTION OR REPULSION of each charge has a magnitude and a DIRECTION, thus being a vector quantity, because if it just had magnitude it would only be a scalar quantity. Hope that helped.

  5. It is odd that we have all the mathematics, but we have no objective understanding of what charge is! 

  6.  At 10:30 Why when a positive and negative charged object kept close for  Interaction the direction of the lines go from positive to negative?

  7. I don't know if anyone's pointed it out yet (and it's not a big deal because the concept is spot-on) but around six minutes in, Sal says the E-field is 2500, but it should be 2250.

  8. I really appreciate the content but man, did you record that with a hairdryer? Pixels. Pixels everywhere.

  9. i learn more on the comments section… but i thank the vid still… if it weren't for the tree there would be no fruit.

  10. I have seen a definition of field strength = F/Q, but why is that? why not F/(2Q)? or F/Q2?, is this word "strength" related to stress-strength as in mechanics?

  11. I have saved all your videos…if I have any doubts I look upon khan academy , it really makes us learn better …but this video m not satisfied, u confusd me. hope u make other video of this with better explanation…..

  12. so our sun is basically Q, our planets are "baby q", and then that applies to the rest of our planetary systems (obvi atoms as well) and, to follow- our galaxy / Universe. Including black holes which were once the equal to our sun. Which will eventually self destruct and become a black hole … which then creates a new galaxy when the gravity and magnetism attract and form new planets from the destructive aftermath…. the "dust" yes? based on the gravity from the new black hole -creating a new center of gravity?….and this applies to all atoms and any center of "gravity" that creates rotation. but its all basic magnetism. right? curios. sun creates a GIANT charge. attracts our planets (which have minor charge)… its a mirror of the workings of an atom. yes? … … email me if im right or wrong. idk.

  13. just lookin for answers, not mathematics. its obvi not an accident that atoms reflect the solar patterns in our galaxy/ even our Universe. I'm sure the same properties apply in some way shape or form. Enter- magnetic influence. but question – can we relate this entire magnetic influence to dark matter?

  14. My new PHYSICS SOLVING APP.More then 150+ formulas,Solves for any variable you want,Covers up all physics.download now.https://play.google.com/store/apps/details?id=com.physics.lenovo.myapplication

  15. Khan Sir, first day when I watch your videos I was surprised that how one can write in this way …..digitally…and today I am using it perfectly..this is because of you …Thankful to you for this reason…

  16. I am curious about something. At 9:17 in the explanation of field lines around Q, you say, "as you get closer to the source of the electric field the charge gets stronger" I did not know the charge gets stronger or weaker. I thought a charge was a charge, multiples of either negative or positive increments and was fixed. How does the charge get stronger? Does it accumulate more electrons?

  17. I'm very thankful for these videos, they are very interesting and easy to follow. However, I was wondering why the quality (in terms of resolution and drawings) is so low in some videos.

  18. As soon as I heard him say squaler, I scrolled down to see the comments hoping someone commented about it, and low and behold, a comment had been made! Another win for the YT community.

  19. I thought it was E=kQ/r… because if E=Work/Charge, and Work is equal to Force Times distance… then if you derive it in this way, you shoud get E=kQ/r instead of E=kQ/r^2

  20. So my father lives in Germany and sometimes I have to leve school for a month to go to Germany because I want to get a sidesens ship and it messes up my grads and when I come back I have a lot of thing to learn a lot of tests to Wright ect and this helps so much I learn sooo much and dont have to cram physics because when I come back I'm usually in front of the class and what thai learn because of you thank you so much u got a new subscriber

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